A mass M, attached to a horizontal spring, executes SHM with a amplitude A 1 . When the mass M passes through its mean position then a smaller mass m is placed over it and both of them move together with amplitude A 2 . The ratio of
is:
Text Solution
Verified by ExpertsThe correct answer is:
D
C.O.L.M.
MV max = (m + M)V ne , V max = A 1 ꞷ 1
V new = 
V new = A 2 . ꞷ 2
= 
A 2 = 

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